9th class theorem 12.1.4 mathematics 9th class

Theorem 12.1.4

In this video i will tell you about theorem 12.1.4

theorem: Any point on the bisector of an angle is equidistant from its arms. 
  lets see. 
what is about this theorem?
We have an angle and he says any point on the bisector of an angle, so  an angle have a bisecto.
What is bisector? Bisectro bisect an angle in such a way or cuts an angle in such a way that both of two sids angles becomes equal.
After that he says that any point on this bisector. So we takek a point on 'p' whisch is equidistant from its arms. 
So which thing have we need to prove? we have to prove that pis equidistant from its arms A & B. then we contact with B in such condition that 90 dgry angle became. 
And then we contact point 'p' to A lick previous method. Then we became to able to prove point 'p' is equidistant from its arms.  
  Ishfaq learning skills has brought  to you Lecture of Muhammad Ishfaq on "9th Class Mathematics Chapter 12 Line bisector & Angle bisector Mathematics . 

Topic  Theorem 12.1.4
 For more videos of Muhammad Ishfaq visit https://www.youtube.com/channel/UC-ea...

This lecture is specifically recorded for students of 9th class, 9th class from all Punjab Boards and is based on the current syllabus of study for Mathematics book. All these lectures are conducted in Urdu/English medium to facilitate all students. 

 For previous video          https://www.youtube.com/watch?v=khepS...
   https://youtu.be/pIb_MpYrLwQ
  https://youtu.be/XNbnUyZe7Ps